井字棋功能扩展
书中的源码
[Python] 纯文本查看 复制代码 theBoard = {'top-L': ' ', 'top-M': ' ', 'top-R': ' ', 'mid-L': ' ', 'mid-M': '', 'mid-R': ' ', 'low-L': ' ', 'low-M': ' ', 'low-R': ' '}
def printBoard(board):
print(board['top-L'] + '|' + board['top-M'] + '|' + board['top-R'])
print('-+-+-')
print(board['mid-L'] + '|' + board['mid-M'] + '|' + board['mid-R'])
print('-+-+-')
print(board['low-L'] + '|' + board['low-M'] + '|' + board['low-R'])
turn = 'X'
for i in range(9):
printBoard(theBoard)
print('Turn for ' + turn + '. Move on which space?')
move = input()
theBoard[move] = turn
if turn == 'X':
turn = 'O'
else:
turn = 'X'
printBoard(theBoard)
本人改写后的代码
[Python] 纯文本查看 复制代码 theBoard = {'top-L':' ','top-M':' ','top-R':' ','mid-L':' ','mid-M':' ','mid-R':' ','low-L':' ','low-M':' ','low-R':' '}
def printBoard(Board):
s = '-----'
print(Board['top-L'] + '|' + Board['top-M'] + '|' + Board['top-R'])
print(s)
print(Board['mid-L'] + '|' + Board['mid-M'] + '|' + Board['mid-R'])
print(s)
print(Board['low-L'] + '|' + Board['low-M'] + '|' + Board['low-R'])
turn = 'X'
for i in range(9):
if i == 0:
print('欢迎进入井字棋游戏')
d = '''top-L top-M top-R
mid-L mid-M mid-R
low-L low-M low-R'''
print()
print(d)
print()
printBoard(theBoard)
print('Turn for ' + turn + ' 你想要在井字棋的哪个位置着手?')
move = input()
theBoard[move] = turn
if turn == 'X':
turn = 'O'
else:
turn = 'X'
if theBoard['top-L'] == 'X' and theBoard['top-M'] == 'X' and theBoard['top-R'] == 'X':
print()
print('X赢')
print()
elif theBoard['mid-L'] == 'X' and theBoard['mid-M'] == 'X' and theBoard['mid-R'] == 'X':
print()
print('X赢')
print()
elif theBoard['low-L'] == 'X' and theBoard['low-M'] == 'X' and theBoard['low-R'] == 'X':
print()
print('X赢')
print()
elif theBoard['top-L'] == 'X' and theBoard['mid-L'] == 'X' and theBoard['low-L'] == 'X':
print()
print('X赢')
print()
elif theBoard['top-M'] == 'X' and theBoard['mid-M'] == 'X' and theBoard['low-M'] == 'X':
print()
print('X赢')
print()
elif theBoard['top-R'] == 'X' and theBoard['mid-R'] == 'X' and theBoard['low-R'] == 'X':
print()
print('X赢')
print()
elif theBoard['top-L'] == 'X' and theBoard['mid-M'] == 'X' and theBoard['low-R'] == 'X':
print()
print('X赢')
print()
elif theBoard['top-R'] == 'X' and theBoard['mid-M'] == 'X' and theBoard['low-L'] == 'X':
print()
print('X赢')
print()
elif theBoard['top-L'] == 'O' and theBoard['top-M'] == 'O' and theBoard['top-R'] == 'O':
print()
print('O赢')
print()
elif theBoard['mid-L'] == 'O' and theBoard['mid-M'] == 'O' and theBoard['mid-R'] == 'O':
print()
print('O赢')
print()
elif theBoard['low-L'] == 'O' and theBoard['low-M'] == 'O' and theBoard['low-R'] == 'O':
print()
print('O赢')
print()
elif theBoard['top-L'] == 'O' and theBoard['mid-L'] == 'O' and theBoard['low-L'] == 'O':
print()
print('O赢')
print()
elif theBoard['top-M'] == 'O' and theBoard['mid-M'] == 'O' and theBoard['low-M'] == 'O':
print()
print('O赢')
print()
elif theBoard['top-R'] == 'O' and theBoard['mid-R'] == 'O' and theBoard['low-R'] == 'O':
print()
print('O赢')
print()
elif theBoard['top-L'] == 'O' and theBoard['mid-M'] == 'O' and theBoard['low-R'] == 'O':
print()
print('O赢')
print()
elif theBoard['top-R'] == 'O' and theBoard['mid-M'] == 'X' and theBoard['low-L'] == 'X':
print()
print('O赢')
print()
增加的功能 判断X赢还是O赢
源码分析
创建了一个字典 这个字典可以看成抽象的井字棋 字典里面包含了九个键值对 每个键值对表示井字棋的位置与在位置上的标志 所以第一步就完成了 引用书中的一句话
随后创建了一个printBoard函数 调用函数 函数里面会在屏幕打印一个看起来像真实世界的井字棋的字符画
定义了一个变量turn 这个变量表示要添加到井字棋的占位符(我是这么理解的)
随后 进入for循环 循环九次
进行条件判断 如果是第一次进入 就输出提示 然后调用函数 输出一段文本
turn是会发生变化的 第一次为X 第二次就为O 第三次又变化为X 后面的if分支就足以看的出来
[Python] 纯文本查看 复制代码 if turn == 'X':
turn = 'O'
else:
turn = 'X'
要求输入 并将输入值保存到变量move 然后 字典对应的键保存turn的值
[Python] 纯文本查看 复制代码 move = input()
theBoard[move] = turn
这两行代码也可以这么理解 如下
move是对应的是要进行选择的真实世界井字棋的位置 theBoard[move]对应井字棋九个填充位置的标志 你选择哪一个move 那么 你选择的那一个位置就填充一个X或者O这样的标志
第一个 if else 的作用上面讲过了 第二个if elif 的作用简单来说就是判断哪一方赢 X赢还是O赢 如何判断的呢 在真实世界中 把三个相同的标志看成点 如果三个点能连成一条直线 那么就赢了
如何用程序判断 在这里 我是这样想的 把所有预估能赢的路线给写出来 一共八种路线 要么先手赢 要么后手赢 先手用X表示 后手则是O
这段代码可以缩短进行优化 但是 本人有点懒 哈哈 | 
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